Find the point on the hyperbola xy=8 that is closest to the point (3, 0).?
Please show work =) The distance between two points in the xy plane is: D = [(x2-x1)^2 + (y2-y1)^2]^0.5 Let (x1,y1) be the point (3,0), then D is: [(x2-3)^2 + (y2)^2]^0.5, or to save clutter: D = [(x-3)^2 + y^2]^0.5 y = 8/x, so D = [(x-3)^2 + 64x^-2]^0.5 dD/dx = 0.5 [(x-3)^2 + 64x^-2]^-0.5 […]
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