A 0.115-L sample of an unknown HNO3 solution required 48.7 mL of 0.100 M Ba(OH)2 for complete neutralization. What was the concentration of the HNO3 solution?
( 48.7 mL) x (0.100 M Ba(OH)2) x (2 mol HNO3 / 1 mol Ba(OH)2) / (115 mL HNO3) = 0.0847 M HNO3
[“Moles” are not a unit of concentration.]
This is the collective voice of the talented editorial team at Answerprime.com. Committed to delivering high-quality content, this account represents the collaborative efforts of knowledgeable experts. With a passion for research and a dedication to accuracy, Answerprime brings you insightful articles across various subjects. Explore a diverse range of expertise and perspectives curated by the editorial team through the lens of Answerprime.
Latest posts by Answer Prime (see all)
- 7 Reasons To Work In HR - June 24, 2025
- Online Trends That Every Business Needs to Be Aware Of - June 24, 2025
- Economic Impact of Online Entertainment in the USA - June 24, 2025