A 0.115-L sample of an unknown HNO3 solution required 48.7 mL of 0.100 M Ba(OH)2 for complete neutralization. What was the concentration of the HNO3 solution?
( 48.7 mL) x (0.100 M Ba(OH)2) x (2 mol HNO3 / 1 mol Ba(OH)2) / (115 mL HNO3) = 0.0847 M HNO3
[“Moles” are not a unit of concentration.]
Latest posts by Answer Prime (see all)
- Why Mobile Networks Are Treated Differently Online - January 16, 2026
- Invisible Risks in a Connected World: The Small Things We Overlook Every Day - January 15, 2026
- What Is XDR and How It Improves Threat Detection - January 14, 2026
