Reaction 1 reversed: 2CO2 + 3H2O = C2H5OH + 3O2
The reversed reaction has the same magnitude for the enthalpy but with the sign reversed.
So, since reaction 1 has an enthalpy of -1370 kJ/mol – that is it is exothermic, then the reverse reaction has an enthalpy of +1370 kJ/mol and it is endothermic.
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