Find the fourth roots of 16(cos 200° + i sin 200°).?
ie you want y = 16^(1/4)(cos(200 + 360n) + i sin(200 + 360n))^(1/4) where n = 0,1,2,3 etc DeMoivres theorem says this is y = 2(cos(50 + 90n) + isin(50 + 90n)) take n = 0, y = 2(cos(50) + isin(50)) take n = 1, y = 2(cos(140) + isin(140)) take n = 2, y […]
Find the fourth roots of 16(cos 200° + i sin 200°).? Read More »
