Find the fourth roots of 16(cos 200° + i sin 200°).?

ie you want

y = 16^(1/4)(cos(200 + 360n) + i sin(200 + 360n))^(1/4)
where n = 0,1,2,3 etc
DeMoivres theorem says this is

y = 2(cos(50 + 90n) + isin(50 + 90n))

take n = 0, y = 2(cos(50) + isin(50))
take n = 1, y = 2(cos(140) + isin(140))
take n = 2, y = 2(cos(230) + isin(230))
take n = 3, y = 2(cos(320) + isin(320))

Answer Prime

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