If 27.0 g of MgSO4.7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
MGSO4 = 120.3 G/ mol 7H20 = 126 G / mol MGSO4.7H2O = 246.3 Grams per mole molar mass of Anhydrous MGSO4 = 120.3 Divide 120.3 by the hydrated mass of 246.3 SO… Multiply (120.3/246.3) with the mass of sample, which is 27 G, and you get the mass of the sample without the water. […]
