If 27.0 g of MgSO4.7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

MGSO4 = 120.3 G/ mol
7H20 = 126 G / mol
MGSO4.7H2O = 246.3 Grams per mole
molar mass of Anhydrous MGSO4 = 120.3
Divide 120.3 by the hydrated mass of 246.3
SO… Multiply (120.3/246.3) with the mass of sample, which is 27 G, and you get the mass of the sample without the water.
Mass of sample without water is : ~13.2G

Source(s): AP Chem

Answer Prime

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top