Which triangle is similar to triangle EAD using the Pieces of Right Triangles Similarity Theorem?

a) rqs Step-by-step explanation: they are both right angles

B. Triangles are similar if two corresponding angles in each triangle are the same measure. Step-by-step explanation: If two pairs of corresponding angles are congruent, then that makes the triangles similar to each other, by the Angle-Angle Similarity Postulate. * This is definitely a genuine statement! I am joyous to assist you anytime.

Answer 6

ΔSRT and ΔTRP Step-by-step explanation: We are given that R is a point on hypotenuse SP such that the segment RT is perpendicular to PS, therefore, PR=RS as the perpendicular bisector divides the line segment in two equal halves. Now, In ΔSRT and ΔTRP, PR=SR( Since RT is perpendicular bisector, it divides PS in two equal halves) ∠PRT=∠SRT=90° (RT is perpendicular bisector of PS) RT=RT(Common) Therefore, by SAS rule of congruency, ΔSRT ≅ΔTRP Hence, Option D is correct.

I believe the correct answer from the choices listed above is the third option. The pair of triangles that are similar are the triangles PQR and PTS. They both are isosceles triangles with the same ratio of the corresponding lengths. Hope this answers the question. Have a nice day.

The answer is triangle BEC Step-by-step explanation:

Answer 7

A Triangles are similar of one corresponding angle in each triangle is the same measure.

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Triangle d is similar

Triangle CAD Step-by-step explanation:

C. Triangle BEC Step-by-step explanation: Point D is not part of triangle ABC, so the “pieces of a right triangle” similarity theorem cannot apply to any figure containing point D. Also, the middle letter of the triangle designator must be the vertex with the right angle. Only one answer choice remains: Triangle BEC.

Answer 6

ΔSRT and ΔTRP Step-by-step explanation: We are given that R is a point on hypotenuse SP such that the segment RT is perpendicular to PS, therefore, PR=RS as the perpendicular bisector divides the line segment in two equal halves. Now, In ΔSRT and ΔTRP, PR=SR( Since RT is perpendicular bisector, it divides PS in two equal halves) ∠PRT=∠SRT=90° (RT is perpendicular bisector of PS) RT=RT(Common) Therefore, by SAS rule of congruency, ΔSRT ≅ΔTRP Hence, Option D is correct.

You have two given angles of triangle PQR.They are 24 degree and 100 degree.What do those measures add up to? What is 100 + 24? = 124 When you add the measure of the third angle to 124, you must get 180.To find the measure of the third angle, just do 180 – 124.What do you get? 180 – 124 = 56That means the third angle of triangle PQR measures 56 deg.Now we know the measures of all three angles of triangle PQR: 24, 100, 56.Triangle RST has two angles that measure 24 deg. and 56 deg.Since two angles of triangle PQR are congruent to two angles of triangle RST, the triangles are similar.

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Triangle d is similar

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