If the organ pipe is cut in half. what is the new fundamental frequency?

An open organ pipe (i.e.. a pipe open at both ends) of length L_0 has a fundamental frequency f_s If the organ pip is cut in half what is the new fundamental frequency? After being cut in half in partA the organ pipe is closed off at and what is the new fundamental frequency?

As, frequency * wavelength= wave speed
Speed in helium is 3 times that of air as the wavelength will
remain same so frequency has to be 3 times
Therefore f = 3 f0