A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 5.40 kg box that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box.
Net work done on the box equals its change in kinetic energy (Work-Energy Theorem):
1/2 m v^2 = ∫ F(x) dx
1/2* 5.40kg* v^2 = 18.0N * 17m – 1/2*0.530N/m*(17m)^2
2.70kg * v^2 = 229.4 N m
v^2 = 84.97 m^2/s^2
v = 9.22 m/s
This is the collective voice of the talented editorial team at Answerprime.com. Committed to delivering high-quality content, this account represents the collaborative efforts of knowledgeable experts. With a passion for research and a dedication to accuracy, Answerprime brings you insightful articles across various subjects. Explore a diverse range of expertise and perspectives curated by the editorial team through the lens of Answerprime.
Latest posts by Answer Prime (see all)
- If two particles have equal momenta, are their kinetic energies equal? - September 25, 2023
- when a job application asks you starting compensation and ending compensation. What does that mean? - September 25, 2023
- what does a 138 in progress mean? - September 25, 2023
