Find the exact value of cos(2 sin^-1(5/13)) ?
I have no idea how to do this, can some one explain to me step by step? Start out by letting x = arcsin(5/13) so that sin(x) = 5/13. Then, we wish to find: cos[2arcsin(5/13)] = cos(2x). Using the double-angle formula for cosine, we have: cos(2x) = 1 – 2sin^2(x) = 1 – 2(5/13)^2, since […]
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