Calculate the number of molecules/m3 in an ideal gas at STP.
I have to quibble with 1st answerer. At STP (0 C, 100000 Pa; see ref.), volume of 1 mol = 22.711 L. (It’s 22.4 L at 0 C/101325 Pa and 24.4 L at 20 C/100000 Pa, which may be where 24.5 came from.)
Then n (no. of moles) in 1 m^3 = 1000/22.711 = 44.0316 mol/m^3 = 44.0316*Avogadro = 2.65164E25 molecules/m^3.
Ideal Gas At Stp
you know that:
1 mole equals 6.022*10^23 molecules (roughly)
at STP one mole of a gas is 24,5 l.
so:
1 l : 24,5 l/mol = 0,041 mol
(6,022*10^23 mol^-1) * 0,041 mol = 24,6*10^21 molecules
since this is 1 dm^3 you just have to multiply the answer with 1000, so you would get 24,6*10^24 molecules.
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