The potential power of a 25 kg bicycle resting on the prime of a 3 m excessive hill is what?
PE = mghPE = 25 (9.8) (3)PE = 735 J Hope this solutions the query. Have a pleasant day.
Rationalization: Potential power is the power obtained by a substance because of their place. Mathematically, P.E = mgh the place m = mass g = acceleration because of gravity = 9.8 m/s h = peak Since it’s on condition that mass is 25 kg and peak is 3 m. Therefore, calculate the potential power as follows. P.E = mgh = = 735 kg/s Thus, we will conclude that potential power for the given case is 735 kg/s.
735.75 is the reply bud
The potential power of the bicycle is 735 joules. Rationalization: The potential power of the bicycle will be calculated as:
U = W*h
the place W is the load of the bicycle, and h is the peak at the place the bicycle is initially:
W = 25kg*9.8m/s^2 = 245 N and h= 3m
U = 245N*3m = 735N*m = 735 J So the potential power of the bicycle whereas resting is 735 joules.
735 J, I consider Rationalization: The equation for potential power is PE = mgh PE = 25*9.8*3 = 735 J This interprets to roughly 147 lbs of potential power. Hope this helps!
Howdy! The potential power of a 25 kg bicycle resting on the prime of a 3 m excessive hill is _______ J If: 1 Joule = 1 kg.m²/s² We’ve the next information: GPE (Gravitational Potential Power) = ? (in J) m (mass) = 25 kg g (gravity) ≈ 9.81 m/s² h (peak) = 3 m We apply the info to the components of the gravitational potential power, we’ve: 735.75 J ________________________
PE = 735 J Rationalization: PE = mgh: PE = (25)(9.8)(3) = 735 J
The reply is 735.75 J
The right reply is: 735 J The potential power of a 25 kg bicycle resting on the prime of a 3 m excessive hill is 735 J.
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