Solve the following inequality: 38 < 4x + 3 + 7 – 3x. A. x < 28 B. x < 4 C. x > 28 D. x > 4?

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Solve the following inequality: 38 < 4x + 3 + 7 – 3x.

Hi,

Solve the following inequality: 38 < 4x + 3 + 7 – 3x. 38 < 4x + 3 + 7 – 3x 38 < x + 10 28 < x, which is the same as x > 28 when it is reversed.

A. x < 28 B. x < 4 C. x > 28 <==ANSWER D. x > 4

I hope that helps!!

38 < 4x + 3 + 7 - 3x 28 < x Answer choice: C. x > 28

C, since you subtract both sides by 3 and 7 getting you 28<4x-3x. This then leads you to find out that x>28 giving you the answer.

38 < 4x + 3 + 7 – 3x 38 < 4x + 10 - 3x 28 < x (A) Maybe you ask your teacher if it is correct.

23x^2 – 69x = 23x(x-3) #22 If the made of two components is 0, which of here won’t be able to be genuine? A.) the two components are no longer 0 is fake. a million ingredient must be 0. #23 ingredient: X^2 – 7x 12 (x-3)(x-4) #24 ingredient: x^2 6x – 7 (x+7)(x-a million) #25 ingredient: x^2 – 4x – 32 (x-8)(x+4) #30 Use removal to sparkling up the device of equations: -x+ 2y = 18 x + 8y = -38 upload the two eqs 0 + 10y = -20 y= -20 #31 ingredient: x^2 13x 40 two seem lower back at those i’ve got already performed and parent this one out #32 sparkling up: x^2 5x – 14 = 0 (ingredient this one, think of 7 and a couple of) #33 sparkling up here: (q 2)^2 = 25 take the squarert of the two facets #34 sparkling up here: y^2 6y 9 = 40 9 subtract 40 9 from the two facets and then ingredient like above

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