Which does not describe the same situation?

4. Choice third. Step-by-step rationalization: On this query, three choices are given. We have to describe  the identical state of affairs. First choice: y = 3 + 6x this equation signify the equation of a line. In that line all of the factors are associated with one another with identical relation. So, this equation describe the identical state of affairs. Second equation: y is 2 greater than six instances x. We write this example in equation  kind. y  = 6x + 2 that is additionally describe the identical state of affairs. Third choice: this desk reveals the x-y relation desk. Right here no two factors are describe the identical state of affairs. So, choice third does not describe identical state of affairs. Query 5: Please share the choices

For, x = -3; y = 3(-3) + 5 = -9 + 5 = -4For x = 1; y = 3(1) + 5 = 3 + 5 = 8For x = 4; y = 3(4) + 5 = 12 + 5 = 17 Thus the desk representing the operate is the desk with: -3, 1 and 4 as x-values and -4, 8, 17 as y-values. For x = 0; y = 3(0) + 5 = 0 + 5 = 5For y = 0; 0 = 3x + 5; 3x = -5 and x = -5/3 Thus the graph of the operate is a straight line passing by factors (0, 5) and (-5/3, 0). For instance the fuction as a phrase assertion we are saying that y is 5 greater than 3 times x From the given descriptions, the graph doesn’t signify the graph of y = 3x + 5. Due to this fact, the one that doesn’t describe the identical state of affairs is the graph.

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y = 3+6x Step-by-step rationalization: Allow us to substitute x = 0, then we get
y = 3
This isn’t the case because the graph clearly reveals that when x = 3, then y = 2
y = 2+6x
when x = 0 then y = 2 which legitimate from the graph
Now put x values from the desk into the equation
y = 2+6×-1
⇒y = -4
x = 2
y = 2+6×2
⇒y = 14
All of the values match within the equation. So, the underside two choices are legitimate.
Therefore, the primary equation is just not legitimate.