What’s what’s the Lewis structure for 2H2O ​

What’s what’s the Lewis structure for 2H2O ​

Lewis Structure:
H — O — H (bent, Oxygen has 2 lone pairs)
Percent Composition

Hydrogen percent composition = [ 2 * (Hydrogen mass) ] / [Total mass of H2O]

Oxygen percent composition = [Oxygen mass] / [Total mass of H2O] dose this make any sense…??

2 lone pairs of electrons Explanation: In this case, the central atom is oxygen. If we check the periodic table we will have an atomic number of 8. So, the electronic configuration would be: We have 6 electrons in the last level. Therefore, we have 6 valence electrons. For the hydrogens, we will have only 1 electron each. So, in total, we have 8 electrons. With this in mind, we have to draw two lone pairs in the oxygen and 1 bond with each hydrogen. See figure 1. I hope it helps!

Concepts and reason Lewis structure is a structure that explains the bonding between atoms of a molecule and lone pair of electrons that is present in the molecule is called a Lewis structure. With the help  of Lewis structure the electronic geometry of a molecule can be determine. Fundamentals According to Lewis structure, every atom and their position in the structure of a molecule by using its chemical symbol. Lines connecting the atoms that are bonded to them are drawn. Lone pairs are expressed by pairs of dots and are located beside the atoms. Lewis structure  of is, the total number of valence electrons is eight in .

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hydroperoxyethane Explanation: tomsFor the Lewis structure we have to remember that all the atoms must have 8 electrons (except for hydrogen). In this structure, we have three types of atoms, Carbon, Hydrogen and Oxygen. So, we have to remember the valence electrons for each atom: -) Carbon : 4 electrons -) Hydrogen: 1 electron -) Oxygen: 6 electrons We can start with the “” part. We can put 3 hydrogen bond arroun the carbon. We can use this same logic with  “”. Finally for oxygens, we can put it one bond with and a bond between oxygens with a final bond with hydrogen to obtain hydroperoxyethane. See figure 1 for further explanations.

The skeleton structure is H-O-H. O has 6 valence electrons, and each H has one. You must arrange 8 electrons in pairs so that O has 8 and each H has two electrons in its valence shell. You have eight valence electrons in your trial structure, so it has the correct number of electrons. Explanation:

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Answer 6

The skeleton structure is H-O-H. O has 6 valence electrons, and each H has one. You must arrange 8 electrons in pairs so that O has 8 and each H has two electrons in its valence shell. You have eight valence electrons in your trial structure, so it has the correct number of electrons. Explanation: hope this helps please let me know if this does or or doesn’t help best of luc! please rate?

Answer 7

This is an incomplete question, here is a complete question. Draw a Lewis structure for H₂O that obeys the octet rule if possible and answer the following questions based on your drawing. For the central oxygen atom: The number of lone pairs = The number of single bonds = The number of double bonds = Answer : The Lewis structure for H₂O is shown below. For the central oxygen atom: The number of lone pairs = 4 The number of single bonds = 2 The number of double bonds = 0 Explanation : Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. In the Lewis-dot structure the valance electrons are shown by ‘dot’. The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol. In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons. The given molecule is, As we know that hydrogen has ‘1’ valence electrons and oxygen has ‘6’ valence electrons. Therefore, the total number of valence electrons in = 2(1) + 6 = 8 According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons. For the central oxygen atom: The number of lone pairs = 4 The number of single bonds = 2 The number of double bonds = 0

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