What is the value of Q when the solution contains

2.50�10?3M Mg2+ and 2.00�10?3M CO32?

? Q ?3 M M What concentration of the lead ion, Pb2+ , must be exceeded to

precipitate PbF2 from a solution that is 1.00�10?2 M in

the fluoride ion, F? ? Ksp for lead(II) fluoride is

3.3�10?8 .

M K ?8

Write the reaction as follows: – 2.50x103x2.00×103 – 5×106 Therefore, the value of Qis 5×10 Write the reaction as follows: [F-1- 1.0×102 M 3.3×10% [ps*](1.0×10 *)2 Therefore, the concentration of Pb2+ is 3 3x 10-M