What is the total number of atoms in 0.111 mol of Fe(CO)3(PH3)2? Any help would be great, but some sort of an explanation would be ideal. I’m assuming I need to use Avogadro’s Number.

Moles Fe = 0.111

moles C = 3 x 0.111 = 0.333

moles O = 3 x 0.111 = 0.333

moles P = 2 x 0.111 = 0.222

moles H = 6 x 0.111 = 0.666

total moles = 1.67

atoms = 1.67 x 6.02 x 10^23=1.00 x 10^24

Yup you do need Avogadros number, which is 6.022×10^23 particles/mole so we can use this to get rid of moles as our unit, here’s how. In each molecule we have 1 Fe, 3 C, 3 O, 2 P, and 6 H. So this means that we have 0.111 mol Fe, 0.333 mol C, 0.333 mol O, 0.222 mol P and 0.666 mol H. Now we can use Avagadros number.

0.111 mol Fe(6.022×10^23 Fe atoms/mol Fe)=6.68×10^22 Fe atoms. Do this for each element to get

2.00×10^23 atoms of C, 2.00×10^23 atoms of O, 1.34×10^23 atoms of P, and 4.01×10^23 atoms of H. To get the total number of atoms we add up all of our numbers to get

1.00×10^24 atoms.

there are 15 atoms in on molecule of Fe(CO)3(PH3)2 so there are 1.665 moles of atoms in .111 moles of Fe(CO)3(PH3)2 (15 x .111)

1.665 moles x 6.02×10^23 atoms/mole = 1.00×10^24 atoms in .111 mole of Fe(CO)3(PH3)2

Figure out the molar mass of this compound and mutliply by the number of mol so 0.1111 and then mutliply it by avaogardro’s number.

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