What is the title of this picture

с ZOOM + What Is The Title Of This Picture? green -9 10-25-98-3-425-9-17 1 10-14-16-1 8 7 6-1 25-4 -12 -1 -4 -9 2 8 51225-1-3-3-4 TO DECODE THE TITLE OF THIS PICTURE: Solve any equation below and find the solution in the coded title. Each time it appears, write the letter of the exercise above it. Keep working and you will decode the title. Creative Publications 213 PRE-ALGEBRA WITH PIZZAZZI 04 (2n - 5) = 3n + 10 2 (4x + 7) = 2x - 4 N 8 (k + 3) = 12 - 4 0-3 (5-9v) = 25 + 7v A 6x + 4 = 5 (3x + 8) 05 - 11t = 7 (5 -- 2t) 6-2 (18 - 3y) = 7y + 2y M 2 (4a - 12) + 3a = 6a + 1 Ⓡ 9 (2 + w) - 4w = 3 w - 10 O 10u + 7 = 8 (2u - 4) - 9 U 3 (4d + 1) - 90 = 6 (2 - d) Ⓡ6 (1 + 3m) = -8 (-2m + 5) - 4 -14 + 3 (x + 10) = 7 (2x + 4) + X 6р. - (5p + 5) = -8 -- 2(p + 12) PDF Ch 6 Review - Two....pdf PDF 1488_001 (1)-1 (2).pdf Ch 6 Review - Two....pdf 1-2.jpeg PDF 1488_001 (1)-1 (1).pdf Show all х с ZOOM + What Is The Title Of This Picture? green -9 10-25-98-3-425-9-17 1 10-14-16-1 8 7 6-1 25-4 -12 -1 -4 -9 2 8 51225-1-3-3-4 TO DECODE THE TITLE OF THIS PICTURE: Solve any equation below and find the solution in the coded title. Each time it appears, write the letter of the exercise above it. Keep working and you will decode the title. Creative Publications 213 PRE-ALGEBRA WITH PIZZAZZI 04 (2n – 5) = 3n + 10 2 (4x + 7) = 2x – 4 N 8 (k + 3) = 12 – 4 0-3 (5-9v) = 25 + 7v A 6x + 4 = 5 (3x + 8) 05 – 11t = 7 (5 — 2t) 6-2 (18 – 3y) = 7y + 2y M 2 (4a – 12) + 3a = 6a + 1 Ⓡ 9 (2 + w) – 4w = 3 w – 10 O 10u + 7 = 8 (2u – 4) – 9 U 3 (4d + 1) – 90 = 6 (2 – d) Ⓡ6 (1 + 3m) = -8 (-2m + 5) – 4 -14 + 3 (x + 10) = 7 (2x + 4) + X 6р. – (5p + 5) = -8 — 2(p + 12) PDF Ch 6 Review – Two….pdf PDF 1488_001 (1)-1 (2).pdf Ch 6 Review – Two….pdf 1-2.jpeg PDF 1488_001 (1)-1 (1).pdf Show all х

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soli D Sn=30 4 (20-5) -3n+10 8 n-20=3n10 h=6 n – 30 5 =30=6 © 2(4x+7)= -23-4 6x=-18 82tly=22-4 X=-3 ♡ 8 (k+3) = 12K-4 1-4k = – 28 k k 7 8 K + 24 = 12K-4 # -3(5–9v) = = 25+7V 20V = 40 -15+27 V = 25+7V V=2 A 62 +4 = 5(32+8) | 9x = -36 GX+4=15x+40 2-4 CH H D 5-11t =7(5-26) | 3+= 30 5-11t = 35-147 t-10 © -2(18-34) -74+28 -36+64 = 74 tay 64 = 94 +36 -34 = 36 Y = -12
M 2140-12) +32 = 6at) 5a = 25 8a – 24+39 = 6a ti а a =5 5 lla-24 =bat ® 9(2+w) – yw = 3W-1012W —28 W=-14 18+9W 4W =3W-10 18+zw=-10 U u=8 100 + 7 = 8(24-4)-9 Gu=48 lou +7=16u -32-9 lou +7 16U – 41 = 3(ud + 1) -9d=612-d) | ad = 9 q 120 +3-9d =12-6d d1 3d76d = 12-3 6 (1+3m) = -8 (-2m +5) -4 11 R G + 18 m =’+16m –40.-4 2m =-44-6 2m – 50 m m -25
€ -14 + 3(x+io) = 7(2x + 4) + X -14+34 +30 =1 4x + 28+ x 16 +32 = 152 + 28 -12-122 2 = -1 © Gp – (sp+5) = -8 -2(P+12 GP – 52–5 = -8 -28 – 24 P 5 = -32 -2P 3p =-27 3P -.5=-32 Р p. -9 Title of the picture I Bay D. L N НА с B м РотR E V u v 2 -4 10 +2 5 -14 -14 8 I-25 -1 un 6 -3 7 ㄱ – 9 CIRCULAR CENTIPEDE UNDER ABEACH UMBRELLA Title CIRCULAR CENTI PEDE BLA UNDER A BEACH UMBRELLA

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