# What is the strength of the field at point 1 in (figure 1).

Part A Part A What is the strength of the field at point 1 in (Figure 1) . Part B Part B Select the correct direction of the field at point 1.

A. down

B. up

C. right

D. left
Part C
What is the strength of the field at point 2 in (Figure 1) .
Part D
Select the correct direction of the field at point 2.

A. left

B. right

C. down

D. up

A. down

B. up

C. right

D. left
Part C
What is the strength of the field at point 2 in (Figure 1) .
Part D
Select the correct direction of the field at point 2.

A. left

B. right

C. down

D. up

A. down
A. down
B. up
B. up
C. right
C. right

D. left
Part C
What is the strength of the field at point 2 in (Figure 1) .
Part D
Select the correct direction of the field at point 2.

A. left

B. right

C. down

D. up

D. left
Part C
What is the strength of the field at point 2 in (Figure 1) .
Part D
Select the correct direction of the field at point 2.

A. left

B. right

C. down

D. up

Part C Part C What is the strength of the field at point 2 in (Figure 1) . Part D Part D Select the correct direction of the field at point 2.

A. left

B. right

C. down

D. up

A. left

B. right

C. down

D. up

A. left
A. left
B. right
B. right
C. down
C. down
D. up
D. up Figure 1 of 1 0 V 0 m. 1 m. 10V 2 m 20V 3 m. 30 V 400 V 4 m

we know that electric field E=V/d
A))).from graph, for point 1   V=V2-V1
=(10-0)=10V & d2-d1=2-0=2m
so E=10/2=5 V/m & it is in lft direction
B))).for point 2,,, V=v2-v1
=40-20=20 V &d2-d1=4-3=1 m
E=v/d
E=20/1=20 V/m& it is left direction    