What is the net ionic equation of the reaction of BeCl2 with NaOH?

Complete ionic equation:
Be2+(aq) + 2 Cl-(aq) + 2 Na+(aq) + 2 OH-(aq) –> Be(OH)2(s) + 2 Cl-(aq) + 2 Na+(aq)

Net ionic equation:
Be2+(aq) + 2 OH-(aq) –> Be(OH)2(s)

See http://www.csudh.edu/oliver/chemdata/solrules.htm

Be is group 2 so I expect its hydroxide to be slightly soluble but according to http://en.wikipedia.org/wiki/Beryllium_hydroxide its solubility is negligeble

so

Be^2+(aq) + 2 OH^-(aq) —> Be(OH)2(s)

BeCl2 + 2NaOH –> Be(OH)2(s) + 2NaCl(aq)

net:
Be 2+ + 2OH- –> Be(OH)2(s)