What is the mass of 0.500 mol of dichlorodifluoromethane, CF 2Cl2 (show work)?

1- (aq) calcium phosphate reacts with sulfuric acid to form solid calcium sulfate and phosphoric acid. Write the balanced equation showing proper state of each reactant and product

I just asked a solution stoichiometry problem on here but i’ll take a crack at this
1. Ca3(PO4)2 (aq) + 3H2SO4 (aq) –> 3CaSO4 (s) + 2H3PO4 (aq)
2. for this one you’ve got .5 mol CF2Cl2 so you simply need to convert it to grams
.500 mol CF2Cl2 x 121 g CF2Cl2/ 1 mol = 60.5 g CF2Cl2
pretty sure this is right. we passed this unit a while back

1.) Ca3(PO4)2 + 3H2SO4 -> 3CaSO4 + 2H3PO4
2.) .500 mol x molar mass of CF2CL2
.500 mol x 120.89g / 1 mol = 60.45g

DCDFM has MW of 120.93g/mol so 0.5 mol = 60.465g

What Tinman said…

DO YOUR OWN HOMEWORK!

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