A parallel-plate capacitor is shaped from two 1.0 cm x 1.0 cm electrodes spaced 2.4mm aside. The electrical discipline energy contained in the capacitor is 1.0*10^6 N/C .
Q = CV = (εₒA/d)(Ed) = εₒAE = (8.85×10^-12)(0.01)²(10^6)
= 8.85 x 10^-10 C
So we’ve
+0.885 nC on the optimistic electrode and
-0.885 nC on the unfavorable electrode.
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