Two traveling sinusoidal waves are described by the wave functions where x, y1 and y2 are in meters and t is seconds.

Answer

You can use the trig identity sin u + sin v = 2 sin(½(u+v)) cos(½(u−v)) with u=4.30x – 1260t and v=4.30x – 1260t – 0.25. You should find that the resultant wave is given by 2*(5.45m)* sin(4.3x-1260t-.125) *cos(.125). That means: a) The amplitude is 2*(5.45m)*cos(.125) =10.81m b)The frequency is the same as it was for y1 and y2: the angular frequency w =1260 rad/s or f = w/(2*Pi) = (1260 rad/s)/(2*Pi rad) = 200.5 Hz. Hope that helps!

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