The position of a rabbit along a straight tunnel as a function of time is plotted in the figure.

the career of a rabbit along a straight tunnel as a function
of the time is plotted when you look at the figure. The position of a rabbit along a straight tunnel as a function
of time is plotted in the figure.

a.) What is its instantaneous velocity at t=10.0s?
b.) What is its instantaneous velocity at t=30.0s?
c.) What is its average velocity between t=0 and
t=5.0s? 
d.) What is its average velocity between t=25.0s and
t=30.0s?
e.) What is its average velocity between t=40.0s and
t=50.0s? a.) what exactly is its instantaneous velocity at t=10.0s? t b.) what exactly is its instantaneous velocity at t=30.0s? c.) what exactly is its typical velocity between t=0 and
t=5.0s? t t d.) what exactly is its typical velocity between t=25.0s and
t=30.0s? t t age.) what exactly is its typical velocity between t=40.0s and
t=50.0s?
t t

-(a) Make a tangent range at t = 10 s to get the instantaneous
velocity by its pitch. Here is the less high regarding the two blue outlines
overhead. This range seemingly have a pitch of rise/run = 14 m/50 s =
.28 m/s
-(b) Make a tangent
range at t = 30 s, in order to find its pitch (this is basically the velocity). This
may be the steeper regarding the two blue outlines. This range rises 25 m between
17 and 37 moments, so that it has actually a pitch around 25 m/20 s, that is
about 1.25 or 1.2 m/s.
-(c) Normal velocity
is simply complete displacement split by complete time. From 0 to 5
moments this indicates going from 0 to about 1.5 m (look over through the graph),
and also the time is naturally 5 moments, so that the typical velocity is 1.5
m/5 = .3 m/s
-(d) From 25 to 30
the bunny displaces from 8 m to 16 m (look over through the graph), once again
in 5 moments offering a typical velocity of 8m/5 s = 1.6 m/s
-(e) From 40 to 50
moments the bunny displaces from 20 m to 10 m (look over through the
graph), today in 10 moments offering a typical velocity of -10m/10s =
-1.0 m/s

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