the career of a rabbit along a straight tunnel as a function

of the time is plotted when you look at the figure. a.) what exactly is its instantaneous velocity at t=10.0s? t b.) what exactly is its instantaneous velocity at t=30.0s? c.) what exactly is its typical velocity between t=0 and

t=5.0s? t t d.) what exactly is its typical velocity between t=25.0s and

t=30.0s? t t age.) what exactly is its typical velocity between t=40.0s and

t=50.0s?

t t

-(a) Make a tangent range at t = 10 s to get the instantaneous

velocity by its pitch. Here is the less high regarding the two blue outlines

overhead. This range seemingly have a pitch of rise/run = 14 m/50 s =

.28 m/s

-(b) Make a tangent

range at t = 30 s, in order to find its pitch (this is basically the velocity). This

may be the steeper regarding the two blue outlines. This range rises 25 m between

17 and 37 moments, so that it has actually a pitch around 25 m/20 s, that is

about 1.25 or 1.2 m/s.

-(c) Normal velocity

is simply complete displacement split by complete time. From 0 to 5

moments this indicates going from 0 to about 1.5 m (look over through the graph),

and also the time is naturally 5 moments, so that the typical velocity is 1.5

m/5 = .3 m/s

-(d) From 25 to 30

the bunny displaces from 8 m to 16 m (look over through the graph), once again

in 5 moments offering a typical velocity of 8m/5 s = 1.6 m/s

-(e) From 40 to 50

moments the bunny displaces from 20 m to 10 m (look over through the

graph), today in 10 moments offering a typical velocity of -10m/10s =

-1.0 m/s