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Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. your calculator answer would be 11.76 cm2 . now suppose you are asked to enter the answer to two significant figures. (note that if you do not round your answer to two significant figures, your answer will fall outside of the grading tolerance and be graded as incorrect.)

12 square cm correct to 2 significant figures Step-by-step explanation: Area of a Rectangle = L X B = 2.1 X 5.6 = 11.76 square cm To round your result to 2 significant figure, we start counting from the left from the first non-zero digit. The first two digits are 11 but because the number after is 7 (greater than 4), we round up to 12. 11.76 square cm = 12 square cm correct to 2 significant figures

Step-by-step explanation: We are given that Width of rectangle=b=2.1 cm Length of rectangle=l=5.6 cm We have to find the area of rectangle. We know that Area of rectangle= Using the formula Area of rectangle = Area of rectangle= Hence, the area of rectangle=

Area can be calculated by multiply these two numbers 2.1-cm and 5.6 –cm and got 11.76 cm 2. Further Explanations:

Area Calculation

Area of square:

Area can be calculated by multiplying the base and height it depends on you that which area is you want to calculate. If you want to calculate the AREA OF SQUARE That formula for square is side of square is multiplied by side of the sane square. Area of Triangle:

If you want to calculate the area of the rectangle than you have to use he formula of ½ * Base* Height.

Area of rectangle: If you want to calculate the area of rectangle than area of rectangle can be calculated by formula as base * Height. Because rectangle ha two side equals

Two significant figures:

The condition of the question is this that there should be only two significant numbers means after the do of the number there are only two digits.If you have more than digits than the rules of significant digits should be applied on them.

Answer Details:

Subject: Physics

Level: Middle School

Key Words:

Area of square Area of Triangle

Area of rectangle: Two significant figures

For further Evaluation:

The area of a rectangle whose length is 5.6 cm and the width is 2.1 cm to two significant figures is 12 cm ². Further Explanation Area Area is a measure of how much space is occupied by a given shape.Area of a substance is determined by the type of shape in question. For example; Area of a rectangle is given by; Length multiplied by width Area of a triangle = 1/2 x base x height Area of a circle = πr². where r is the radius of a circle, Area of a square = S², Where s is the side of the square.etc. Perimeter Perimeter is defined as the distance along a two dimension shape. Perimeter of different shapes is given by different formulasFor example The perimeter of a rectangle = 2(length+width) The perimeter of a triangle = a+b+c; where a, b and c are the sides of the triangle. etc. In this question The rectangle has a; Length = 5.6 cm Width = 2.1 cm Area of a rectangle = length × width = 2.1 cm × 5.6 cm = 11.76 cm² The area of the rectangle to two significant figures is 12 cm² Keywords; Area, Area of a rectangle Learn more about;Area: Perimeter: Area of a rectangle: Level: Middle school Subject; Mathematics Topic: Area and Perimeter

The area of the rectangle is 12 cm² ⇒ in 2 significant figures Step-by-step explanation: * Lets talk about the significant figures – All non-zero digits are significant # 73 has two significant figures – Zeroes between non-zeros digits are significant # 105.203 has six significant figures – Leading zeros are never significant # 0.00234 has three significant figures – In a number with a decimal point, zeros to the right of the last non-zero digit are significant # 19.00 has four significant figures – Lets make a number and then approximate it to different significant ∵ 12.7360 has 6 significant figures ∴ 12.736 ⇒ approximated to 5 significant figures ∴ 12.74 ⇒ approximated to 4 significant figures ∴ 12.7 ⇒ approximated to 3 significant figures ∴ 13 ⇒ approximated to 2 significant figures ∴ 10 ⇒ approximated to 1 significant figure – Another number with decimal point ∵ 0.0546700 has 6 significant figures ∴ 0.054670 ⇒ approximated to 5 significant figures ∴ 0.05467 ⇒ approximated to 4 significant figures ∴ 0.0547 ⇒ approximated to 3 significant figures ∴ 0.055 ⇒ approximated to 2 significant figures ∴ 0.05 ⇒ approximated to 1 significant figures * Lets solve the problem ∵ The width of the rectangle is 2.1 cm ∵ The length of the rectangle is 5.6 cm – Area of the rectangle = length × width ∴ Area of the rectangle = 2.1 × 5.6 = 11.76 cm² – Approximate it to two significant figures ∴ Area of the rectangle = 12 ⇒ to the nearest 2 significant figures * The area of the rectangle is 12 cm² ⇒ in 2 significant figures

Answer 6

If I’m understanding the question then 11.76cm^2 in two sig figs is 12cm^2. I don’t see a part c to this question though so if I’m not giving you the answer you need please advise and I will answer what you need! Thank you!!

Answer 7

12 cm² Step-by-step explanation: Length of rectangle = 5.6 cm Width of rectangle = 2.1 cm Area of rectangle = Length of rectangle×Width of rectangle ⇒Area of rectangle = 5.6×2.1 ⇒Area of rectangle = 11.76 cm² 11.76 has 4 significant figures in order to write this term in 2 significant terms we round of the term The last digit in the decimal place is 6. Now, 6≥5 so we round the next digit to 8 we get 11.8 Now the last digit in the decimal place is 8. Now, 8≥5 so we round the next digit to 2 we get 12 ∴ Hence the area of the rectangle when rounded to 2 significant figures is 12 cm²

The significant figures need to be counted from first non-zero number at left. So put the 11.76 to two significant figures is 12. The unit is cm2. So the answer is 12 cm2.

so it will be 11.76 = 12 bc 7 rounds up

### What our team says

# Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. your calculator answer would be 11.76 cm2

## Introduction

We all use calculators every day, whether we are using them to work out our taxes or measuring the length of something. But what if you were asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long? Your calculator would tell you that the area is 11.76 cm2. This is because calculators work with rectangular shapes and calculate the area of each side of the rectangle separately. To find the area of a curve, like a rectangle, we need to use calculus – a complex subject that can only be explained in depth by experts. But what if we didn’t have to use calculators? What if we could just use software? In recent years, there has been a lot of development in AI-powered software that can do calculations for us. This means that, in the future, copywriters might not have to use calculators when they are writing content for websites or blog posts. Instead, they could simply type in the information they need and the software would do the calculations for them! So far, this technology has been used mainly for maths and scientific calculations, but it is likely that it will be used more and more in the

## Problem Statement

When given the dimensions of a rectangle, you might be asked to find the area. However, calculating the area of a rectangle can be difficult. In this article, we will discuss how to find the area of a rectangle using basic algebra.

To find the area of a rectangle, you need to solve for x and y. To do this, you will use algebraic equations. First, solve for x:

x = .-. cm

Next, solve for y:

y = .-. cm

Now combine these results to solve for the total area:

A = .-. cm by .- cm

## Solution

Suppose you are asked to find the area of a rectangle that is .-cm wide by .-cm long. your calculator answer would be . cm. To find the area of a rectangle, you use the formula A = (w*h)2. In this case, the width and height are both .-cm, so the answer would be (.-.08)*(.-.08)2 or .0008 cm2.

## Conclusion

In this concluding paragraph, we provide an answer to the question posed in the body of the article. The area of a rectangle is found by multiplying its length and width together. In this case, the length is 5.6 cm and the width is 2.1 cm, so the area would be 11.76 cm2

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