Predict the amide product of the following reaction: Please Help?

Butanoic acid + methylamine—>product + H2O.

CH3CH2CH2CONHCH3.

N-methylbutanamide

To call this amide:
1. Drop the -oic acid from the title of the guardian natural acid and substitute -amide.
So, butanoic acid turns into butanamide.
2. For the reason that amine is major (methylamine), you need to point out the alkyl group connected to the nitrogen. So, this turns into N-methyl.
3. Put these collectively:
N-methyl + butanamide = N-methylbutanamide

**if the amine is secondary, you need to point out each substituents. instance, dimethylamine turns into N,N-dimethyl

Butanoic Acid + Methylamine -> N-Methylbutaneamide

H3CCH2CH2CO-NH-CH3

Also Read :   Which of the following is true about the minoans?

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