In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s. Assuming that the player accelerates uniformly, determine the distance he runs.
acceleration is constant. therefore, change in velocity/change in time = acceleration.
acceleration = 4m/s^2
now you need the equations of motion.
one of them is
s = ut + 1/2*a*t^2
s= displacement (distance)
u = initial velocity (initial speed)
a = acceleration
t = time.
just plug the numbers in…
s = 0*1.5 + 1/2*4*1.5^2
The equation you’re looking for is one of the equations of motion:
s = (v + u)t / 2
u = 0m/s (initial speed) v = 1.5m/s t = 1.5s s = ?m (distance)
s = (6 + 0) x 1.5 / 2 = 4.5 metres
The equation basically says that the distance is equal to the average speed [(v+u)/2] multiplied by the time taken.
S = the distance
U = the initial velocity
V = the final velocity
t = time
S = 0.5 x (0+6.0) x 1.5 = 4.5 meters
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