In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s. Assuming that the player accelerates uniformly, determine the distance he runs.

acceleration is constant. therefore, change in velocity/change in time = acceleration.

acceleration = 4m/s^2

now you need the equations of motion.

one of them is

s = ut + 1/2*a*t^2

where

s= displacement (distance)

u = initial velocity (initial speed)

a = acceleration

t = time.

just plug the numbers in…

s = 0*1.5 + 1/2*4*1.5^2

= 4.5m

The equation you’re looking for is one of the equations of motion:

s = (v + u)t / 2

u = 0m/s (initial speed) v = 1.5m/s t = 1.5s s = ?m (distance)

s = (6 + 0) x 1.5 / 2 = 4.5 metres

The equation basically says that the distance is equal to the average speed [(v+u)/2] multiplied by the time taken.

S=0.5(U+V)t

S = the distance

U = the initial velocity

V = the final velocity

t = time

S = 0.5 x (0+6.0) x 1.5 = 4.5 meters

simples

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