# if dy/dx= ysec^2 x and y=5 when x=0, then y=?

In this problem, you are given a function y() that is defined at two points in space, x=0 and x=5. You are asked to calculate y when x is equal to 0 or 5.

## If dy/dx= ysec^x and y=when x=0, then y=?

If dy/dx= ysec^x and y=when x=0, then y=?

The answer to this question is yes. In this equation, y = when x = 0. This means that y equals the value of x when x equals zero.

## Using the Quadratic Formula to solve for y in the equation above

If dy/dx= ysec^x and y= when x=, then y=?

The equation above can be solved using the Quadratic Formula. To do this, we need to find the value of y that corresponds to when x=. To do this, we use the Quadratic Formula:

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y = (y + h)^2

## Rounding off solutions to the equation above to find a final answer

If dy/dx= ysec^ x and y= when x=, then y=?

The equation above can be solved for y by rounding off the solutions to the equation. In this case, y will be equal to when x equals zero. Therefore, y would be equal to zero if and only if dy/dx=0.

## Conclusion

According to the law of cosines, when x=0, y=5.

## FAQ

If dy/dx= ysec^ x and y= when x=, then y=?

The answer to this question is yes. If dy/dx= ysec^ x and y= when x=, then y=ysec. This is because ysec is the derivative of y with respect to x.