If a non-cyclic alkane shows a molecular ion peak at m/z 268, what is the chemical formula? C? H?

The chemical formulation can be C19H40, which is nonadecane.
We all know that for an aliphatic alkane, if there are n C atoms, there are 2n + 2 H atoms. Taking the mass of C (12) and the mass of H (1), we will arrange the next equation:
12n + 2n + 2 = 268
14n = 266
n = 19
So if there are 19 C atoms, there are 2(19) + 2 = 40 H atoms.
This offers you the formulation C19H40.

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