How many moles of O2 are produced when 0.425mol of KO2 reacts in this fashion?

Using the chemical equation: 4KO2+2CO2→2K2CO3+3O2 What variety of moles of O2 are produced when 0.425 mol of KO2 reacts on this fashion? Moreover, what variety of grams of KO2 are wished to sort 6.5g of O2? And what variety of grams of CO2 are used when 6.5g of O2 are produced?

So it’s primary math. prepare the equation and put the phrases into math.
1) 0.425 mol x 3mol/ 4mol = .319 mol
2) 6.5g x 188g / 32g = 38.2 grams —-> convert to formulation weight
3) 6.5g x 44g / 32g = 8.9 grams

Provide(s): been engaged on these in class

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