We start with 1KClO3→KCl+O2

Balance K

: We have 1 K

on the left, so we need 1 K

on the right. We put a 1

in front of the KCl

. 1KClO3→1KCl+O2

Balance Cl

: Cl

is already balanced, with 1 Cl

on each side. Balance O

: We have 3 O

atoms on the left and only 2

on the right. We need 1½ O2

molecules on the right. Uh, oh! Fractions! We start over with a 2 as the coefficient. 2KClO3→2KCl+O2

Now we have 6 O

atoms on the left. To get 6 O

atoms on the right, we put a 3 in front of the O2

. 2KClO3→2KCl+3O2

Every formula now has a fixed coefficient. We now should have a balanced equation.

fdvwsa gfwsargebgeebbfwfwffw gwf vgwgw gw f gwgw fgw v v dsv dwfff

it would be a gas formation