For what value of the constant c is the function f continuous on

(-infinity, infinity)? f(x) =cx2 + 8x if

x < 3 cx 2 x x < 3 =x3? cx
if x ?
3
= x 3 ? cx if x ?
3

cx2 + 8x =

x3 ? cx

put x=3

9c+24 = 27 – 3c

c=1/4

f(3-) = c*32 + 8*3 = 9c+24

f(3+)= 33-3c = 27-3c

to make the function countinous f(3-) =

f(3+)

9c+24 =27-3c

12c= 3

c= 1/4