http://session.masteringphysics.com/problemAsset/1…

It is neither series or parallel. It is a 2 mesh circuit or a 1 node.

We know the 2 – 24 resistors are in parallel with each other and must have the same voltage (both of their ends are connected to each other). We know the voltage across the top right 24Ω must be 0.5*24Ω = 12V so the vertical 24Ω also has 12V. That means there must be 0.5A down into the vertical 24Ω resistor. This means there must be 0.5+0.5 = 1A from left to right through the 12Ω resistor. That 1A divides in half at the junction of the 2 – 24Ω resistors which makes sense since it sees 24Ω in each path. The KVL around the left loop in a clockwise direction is

+E – 12V – 12V = 0 => E = 24V

OR we could see there are 2 – 24Ω in parallel in the right loop = 12Ω. Thus E sees 12Ω+12Ω = 24Ω and there is 1A out of E so E = 1A*24Ω = 24V

OR we could solve using a single node V just above the vertical 24Ω:

(V-E)/12 + V/24 + V/24 = 0 But we know V = 0.5A*24Ω = 12V (bottom of circuit chosen to be ground) so set V = 12

(12-E)/12 + 12/24 + 12/24 = 0

12/12 + 12/24 +12/24 = E/12

12 + 6 + 6 = E = 24V

- Did lil Kim really get her stomach pumped from all the ounces of “love juice” what was found in her stomach? - January 31, 2023
- Do you save time with online grocery shopping? - January 31, 2023
- “I am worried as to the health of Don Shane Detroit’s Channel 7 for sports? - January 30, 2023