curvature is | r’ x r”| / | r’ | ^3

r'(t) = <9,2t,3t^2>

r”(t) = <0,2,6t>

r’ x r” = <6t^2 , -54t , 18>

at t = 1 , |r’ x r”| = sqrt(6^2 + 54^2 +18^2) = 57.24

|r’| = 9.7

| r’ x r”| / | r’ | ^3 = 57.24/9.7^3 = 0.063

Latest posts by Answer Prime (see all)

- Evaluate the dot product of the vectors in (figure 1). - November 27, 2022
- Interdependence of firms is most common in - November 27, 2022
- Portions of the financial statements for parnell company are provided below. - November 27, 2022