x y z

Get the part of the area. The an element of the jet 5x+2y+z-10 that is based on the very first octant offered jet 1s 5x+2y+2=10 therefore, 2, 2. area is dA 30dA in which dAis the location of jet we possess the limitations since offered jet is based on the very first octant, z 5x+2y+z 10 0 5x+2y-10 therefore, 0 sx S2. since z 2 0 →10-5x-2y20 therefore, 0 y 5–х. 4 10-5 for that reason, area is 530