Find an equation of the tangent line to the curve at the given point. y = x . (81. 9)

Find an equation of the tangent line to the curve at the given point. y = Squareroot x, (81, 9) y = discover an equation of tangent range into the bend at provided point. y = Squareroot x, (81, 9) y =

y = Jr.(819) Differentiatıng with value x, we have dx 2V812(9) 18 The equation of tangent with pitch 13 together with point (819) is y-9–(x-81) 181 1818 18 2 182 -9+18 18 2
Find an equation of the tangent line to the curve at the given point. y = Squareroot x, (81, 9) y =

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