Determine the [OH-] concentration of a 0.116 M Ba(OH)2 solution at 25°C.?

There are 2 mol OH- for every 1 mol Ba(OH)2, so:

0.116 x 2 = 0.232 M

0.116×2=0.232
pOH= -log(0.232) = 0.6345
pH= 14 – 0.6345
pH= 13.36

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