Determine the [H3O+] in a 0.265 M HClO solution. The Ka of HClO is 2.9 × 10-8.?

Utilize Ka equation:
Ka = [H+]² / [HClO]
2.9*10^-8 = [H+]² / 0.265
[H+]² = (2.9*10^-8)* 0.265
[H+]² = 7.68*10^-9
[H+] = 8.77*10^-5M
[H+] = [H3O+] = 8.77*10^-5M

Leave a Comment