Determine F_12 and F_21 for the following configurations using the reciprocity theorem and other basic shape factor relations. Do not use tables or charts. (a) Long duct (b) Small sphere of area A_1 under a concentric hemisphere of area A_2 = 2A_1 (c) Long duct. What is F_22 for this case? (d) Long inclined plates (point B is directly above the center of A_1) (e) Sphere lying on infinite plane
As per Chegg guidelines, in a given
question we have to answer only 4 sub parts. Therefore, iam
providing the answer for cases a to d only.
In this given question, for given
different configurations we have to find the view factors as
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soluhon case tong duct k-9 ACCOTding ProperHes Of Shape Sactor, configuration, his type of For Fi2 By law of tecipsocihy A F21 A) Fi2 AIX Fi F21 A2 2 RL 3 2RL 4 6.424 4 3T 117 F21 Answer
Cb) case Smail Sphere aotea A under a Concentric hemt-s ehere of n2 2A aote a AI Small sphere tlere Con see , we Concentric hemis phere A2 is undeya SummaHon sule, FO1om Fi+FI2 tfi 1 By Symmehy, F12Fi3 O.5 Fi2 There fore AI Fia A2 Fa By 91eci procily AIX Fi F21= A2 x 0.5 2 A1 0.25 nguwer
Cafe Co Long A By inspecHon From Propeshes O view factor For Such confi qura hon, By Reciprocihy AI FI2 21-01 Fi A 2 2 RL xI T)RL E 2 2 O.64 F =O.637 By summaHon rute =1-0.64 1-F21 F22 (OT) = 1-O637 O.363 (Anf)
Case cd) ong inclined plates A 2 By Summato Role Futfia tF13- By symmetry Fi-FI3 Y Fi2 0.5 By teciprocihy, A2 f2 AIF12 AIXFI2 200XL xO.S L 60 2) F2 O.7o7
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