Consider a fusion reaction in which a proton fuses with a neutron to form a deuterium nucleus.

The decay reaction is, H (proton ) n-in The reduced mass is calculated as follows: = 1.0072766 u +1.0086654 u-201355u = 0.002392 u The energy released in the reacti on is, E=&me = [ 0.002392 u1 315 MeV/c2 2.228 MeV 2.23 MeV s2.3 MeV [0.002392 u]
Consider a fusion reaction in which a proton fuses with a neutron to form a deuterium nucleus. How much energy is released in this reaction?(The mass of the deuterium nucleus is 2.01355u). Answer in MeV

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