Calculate the equilibrium constant. k. for the following reaction at 25 °c.

determine the balance continual, K, the after
effect at 25 °C. Calculate the equilibrium constant, K, for the following
reaction at 25 °C.

Fe3+(aq) + B(s) + 6H2O(l)  Fe(s)+ H3BO3(s) + 3H3O+(aq) The balanced reduction half-reactions for the above equation and their respective standard reduction potential values (E degree) are as follows: Fe3+(aq) + B(s) + 6H2O(l) Fe(s)+ H3BO3(s) + 3H3O+(aq) The balanced decrease half-reactions the preceding equation and their particular particular standard decrease potential values (age level) tend to be the following:

T-273+25 293K RT nF RT E° 2.303logK (2.303-=0.0591) E’= 0.0391 logKeq (letter -3 moles of electrons) Eoー-0.04-(-0.8698)= 0.8298 .milo K -0.8298×3 = logK, 0.0591 logKa, 42.12182 Keg = 104212182 Keg =1.32×1042
Calculate the equilibrium constant, K, for the following
reaction at 25 °C.

Fe3+(aq) + B(s) + 6H2O(l)  Fe(s)+ H3BO3(s) + 3H3O+(aq) The balanced reduction half-reactions for the above equation and their respective standard reduction potential values (E degree) are as follows:

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