Based on the first and fourth sketches (Part C figure) , what is the density of the block?

The block was originally 50.0 grams. Here is the Part C figure…

Hi Andrew!

My suggestion is as follows:

The difference among the two weights corresponds to that of the liquid that has been moved, that is a quantity of liquid whose volume is equal to that of the solid in examination.

……………………… weight in air
Density = —————————————————
……………(weight in air – weight in the liquid)

……………50/(50 – 5.6) = 50/44.4 = 1.12612 g/cm^3

In conclusion, the density is for definition the ratio between the weight in air of a solid and the loss of weight that happens when it is dipped in a liquid.

Bye from Italy,

C6H6

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