A. The activation power of a specific effect is 36.8 kJ/mol at

28 levels celsius the price continual is 0.0190s^-1 at just what

heat in levels celsius would this effect get doubly

quickly? B. considering that the first price constant is 0.0190s^-1 at an

preliminary heat of 28 levels celsius just what would the price

continual be at a heat of 150 levels celsius for similar

effect descrabed partly A?

General assistance

Ideas and explanation

Activation power:

The minimal power that’s needed is when it comes to reactant particles to conquer the vitality buffer for doing the effect. Arrhenius equation provides connection between heat and activation power.

Principles

Arrhenius equation: The interactions between price continual and activation power

In Which

The price continual at heat 1 is.

The price continual at heat 2 is.

The effect heat 1 is actually for.

The effect heat 2 is actually for.

The activation power when it comes to effect is.

The universal fuel constant is roentgen ()

Step by step

Step one of 2

(A)

Provided information,

Replace the values inside Arrhenius equation,

After that on resolving

Component A

The heat regarding the effect in level Celsius is

The offered worth of heat was presented with in level Celsius; the transformation into Kelvin ended up being done-by incorporating the aspect of 273.

The heat regarding the effect ended up being determined by replacing the values of activation power, universal fuel continual, and offered conditions inside Arrhenius equation.

Kindly be mindful while composing the Arrhenius equation at two various conditions.

Sample:

Correct

Wrong

Discover price continual byusing the Arrhenius equation.

2 of 2

(B)

Provided information,

Replace the values inside Arrhenius equation,

After that on resolving

Component B

The worth of k, price continual at 150 levels Celsius, if = 36.8 kJ/mol is .

The offered values of heat have been in level Celsius to transform into Kelvin, it absolutely was included the aspect of 273.

The price continual is determined by replacing the values of activation power, universal fuel continual, as well as 2 various conditions.

Make sure that the ln ended up being expressed in proper way

Sample:

Correct

Wrong

Response

Component A

The heat regarding the effect in level Celsius is

Component B

The worth of k, price continual at 150 levels Celsius, if = 36.8 kJ/mol is .

Response just

Component A

The heat regarding the effect in level Celsius is

Component B

The worth of k, price continual at 150 levels Celsius, if = 36.8 kJ/mol is .

E1 1 In k,

k

k

т, 2

Е,

8.314 J mol K

E -36.8×10 J/mol k 2xk T 28+273 301K roentgen 8.314 J mol K

k2 In Е, k 36.8×10’mol 2k In k 8.314 J mol’ к’ (т, 301к 1 -х 1 In(2)-4.4263x| Т, 301K 0.6931 1 1 – 4.4263 Т, 301K

T 315.88K 315.88-273 42.88° C

1 Е, 1 In k T.

Е. (1 1 RT In k,

E 36.8x10J/mol k 0.0190s T 28+273 301K T 150+273 423K R-8.314 J mol K

E Е, In k, 36.8×10 mol 8.314 J mol K423K 301K k2 1 1 In 0.0190s k2 ( 0.0190s4.4263(2.3640×103-3.3223×10) In k2-In(0.0190)4.4263(-0.9583) In

k2 1.320s

36.8×10 J/mol 8.314 J mol K’ 423K 301K 1 1 In 0.0190s

In k2 -n(0.0190)=4.4263(-0.9583)

36.8×10 J/mol 8.314 J mol K’ 423K 301K 1 1 In 0.0190s

In k2n0.090)=4.4263(-0.9583)

42.88° C

42.88°C

22.64°C

295.64° C.

315° C.

Е,

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