An empty erlenmeyer flask weighs 241.3 g. when filled with water (d = 1.00 g/cm3), the flask and its contents weigh 489.1 g. what

An empty erlenmeyer flask weighs 241.3 g. when filled with water (d = 1.00 g/cm3), the flask and its contents weigh 489.1 g. what is the flask’s volume? how much does the flask weigh when filled with chloroform (d = 1.48 g/cm3)?

Answer

Explanation: Part a. Data Given: weight of the flask = 241.3 g weight of water and flask = 489.1 g density of water = 1 g/cm³ Solution: As we know that the volume of the Erlenmeyer flask is the volume of water that occupied by it. for this first we have to find mass of the water in the Erlenmeyer flask This can be calculated by the subtraction of flask’s weight from the weight of flask and water. weight of water (m) = total weight  – weight of flask put values in the above formula weight of water (m) = 489.1 g –  241.3 g weight of water (m) = 489.1 g –  241.3 g weight of water (m) = 247.8 g To find volume we will use density formula d = m/v rearrange the above equation to calculate volume v = m/d . . .  . . . . (1) put values in equation 1 v = 247.8 g / 1 g/cm³ v = 247.8 cm³ The volume of the Erlenmeyer flask = 247.8 cm³ Part b. Data Given: density of ethanol = 1.48 g/cm³ mass of the flask when filled with ethanol = ? Solution: To find mass we will use density formula d = m/v rearrange the above equation to calculate mass m = d x v . . .  . . . . (2) The volume of ethanol is equal to the volume of Erlenmeyer flask that is calculated in part 1 So, Volume of ethanol = 247.8 g Put values in formula 2 m = 1.48 g/cm³ x 247.8 g m = 366.744 g Now, To calculate total mass of the flask when filled with ethanol. total weight = weight of Erlenmeyer flask + weight of ethanol Put the value in above equation total weight = 366.744 g + 241.3 g total weight = 608.044 g So Total weight of flask and ethanol = 608.044 g

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