An electron at point a in the figure (figure 1) has a speed v0 of 1.10×106 m/s .

An electron at point A in the figure (Figure 1) has a speed v0
of 1.10×106 m/s . a) Find the magnitude of the magnetic field that will cause the
electron to follow the semicircular path from A to
B. A B b)Find the time required for the electron to move from
A to B.
A B

givne
chargeis electron q = – 1.6*10^-19 C,
speed V0 = 1.10*10^6 m/s
moving along the semi circle of lenght pi*r , r is radius of the
circle 5.0*10^-2 m
   here the force acting on the electron is F =
B*q*V fp= mV^2/r     (centripetal
force)
   a)     B = mV^2/(r*q*V) =
m*V/r*q
          = (9.1*10^-31
*1.10*10^6 )/ (0.05*(-1.6*10^-19))
       = 0.000125125 T =
125.125 micro tesla = 1.25125*10^-4 T
B = 1.25*10^-4 T
b) Time taken T = pi*r / V = 3.14*0.05/(1.10*10^6) =
1.42727*10^-7 seconds
T = 1.43*10^-7 s

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