The formula for ammonia is NH3. If you check a periodic table, you can calculate the mass of 1 mole of NH3.
N = 14.01
H = 1.008
So the molar mass (mass/1 mole)
= 14.01 + 3 * 1.008
= 17.034
So there’s 17.034 g NH3 / 1 mole NH3
We want to convert grams to molecules:
56.6g NH3 * (1mol NH3/17.034g NH3)
= 3.323 mol NH3
1 mole of anything has 6.022 x 10^23 of that item.
So 3.323 mol NH3 would have 3.323 x 6.022×10^23 molecules of NH3.
3.323 * 6.022 x 10^23 = 1.945 x 10^24 molecules NH3
Ammonia’s molecular formula = NH3
Average Atomic Mass of…
N=14
H=1
NH3 =
(14+1(3))=17
56.6/17=3.329mol
1mol = 6.022*10^23
3.329*(6.022*10^23)=
2.0047238*10^24 molecules
Since question has 3 significant figures,
The 56.6g sample of NH3 has 2.00*10^24molecules.
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