A projectile is fired with an initial velocity of 120 ms at an angle above horizontal.?

If the projectile’s initial horizontal speed is 55 meters per second, then what will be the angle measured. ( 13-63-27-75) these are the four options

……………_—-_
………._-‾……….‾-_..………..
…… _-‾…………….‾-………….
Vy…/………………………….…
‘.↑../…………………….
..|./.غ )…………’……..
..|/—→Vx____________
▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓…
..|←———– R———-→|
Vy = VsinØ
Vx = VcosØ
For the horizontal motion
Vx = VcosØ
55 = 120(cosØ)
cosØ = 55/120
………= 0.458
Ø = 62.720º
ans = 63º

cosine angle = 55/120 = 11/24
angle = arccosine(11/24) = 62.72 degrees

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