What was the greatest height reached by the ball? Assume it is

kicked from ground level.

With what speed did it leave the kicker’s foot? Answer to two sig. fig. and include the appropriate units.

Include all math(Algerba based) and why that formula was chosen.

Well, we have time, displacement, so we use the kinematic

equation

x=x(initial) + v(initial)t + .5at^2

0 = 0 + v(5.4) + (.5)(-9.8)(5.4)^2

5.4v = 142.884

v= 26.46 ==> 26 m/s as it leaves the kicker’s foot

Now we can use a different kinematic equation now that we know the

initial velocity.

V^2 = v(initial)^2 + 2ax because we know that velocity at max

height is 0 m/s, initial velocity is 26 m/s, and a is -9.8

m/s^2.

(0)^2 = (26.46)^2 + 2(-9.8)x

-19.6x = -700.1316

x= 35.721 ==> 36 meters