An interesting question, which requires thinking carefully about how our common measure of time is related to certain astronomical (solar) positional recurrences. A lot of people (though not all) have answered you as though the year were exactly 365.25 days long on average, but it’s more subtle than that.

There are in fact two particular “years” of interest:

The sidereal year (period of the Earth’s revolution about the Sun with respect to the stars, i.e. operationally, the time for the Sun to apparently “return” to the same position against the stars, after a “year” [crudely 365+ days], as viewed from Earth):

365.256366… days.

The tropical year (time for the Sun to cross the celestial equator [the projection of the earth’s equator in space] again [e.g. from south to north] after a “year” [crudely 365+ days]). Alternatively, “the period of revolution of the Earth about the Sun with respect to the Vernal Equinox”:

365.242199… days.

(Both figures are quoted to an accuracy sufficient for our present purposes.)

These two different “years” differ by just ~20.4 minutes, owing to the precession of the Earth. (One full precession of the Earth’s spin axis in space takes ~25781 years. This long, latter number of years is in fact equal to 365.25 or so days divided by the (essentially observed) “motion of the Vernal Equinox along the celestial equator,” at the rate of ~20.4 minutes per year as just mentioned — check it out. [Sorry about the technical language, but this is technical stuff.])

It’s actually the tropical year that determines the rate at which the observed seasons recur, and since we want them to be “at the same time of the year,” our long-term timekeeping is geared to the tropical, not the sidereal year.

Notice that at 365.242199 days, this “tropical year” is just a tad short of 365.25 days. That’s why, instead of the simplistic idea of a leap year occurring every 4 years (and having an extra day that accounts “exactly” for 4 x the extra 0.25 days), there will come a time when we’ve overcounted a bit.

For example, after 100 years, we should have had 100 x 0.242199 “extra days,” or 24.2199 days. The “one more day every 4th year” rule would give us 25 extra days per century, ~ 0.78 days more than needed. If we could drop just 1 day then, that would be better — but then we’d be under by ~ 0.22 days — aha! — close to a quarter of a day! That’s why the revised rule comes in that complete century years are NOT leap years — UNLESS they’re divisible by 400! (Figure out for yourself from the 365.242199 figure how well this works in the long run. I think you’ll find that the calendar, on average, doesn’t get a full day out of step with these revised rules until something like 3,300 years have gone by!)

O.K., so maybe this is much more than you wanted to know. However, with the right understanding of what the length of the year we usually measure is, 365.242199… days, then 1 million days is 10^6 divided by this, or 2737.90926… years, or 2737 years and 332.10… days.***

*** Remember, this is a mathematically average result, for essentially perfect intervening TROPICAL years (to the accuracy given). If you want to know it in CALENDAR years and a specific whole number of days, the answer will vary slightly about the preceding result, according to when you start counting. This variability is not just because of the usual “every fourth year is a leap year” pattern, but also because of the way that century years aren’t all treated in the same manner. It’s awkward to give a general rule!

Live long and prosper.

The sidereal year (period of the Earth’s revolution about the Sun with respect to the stars, i.e. operationally, the time for the Sun to apparently “return” to the same position against the stars, after a “year” [crudely 365+ days], as viewed from Earth):

The tropical year (time for the Sun to cross the celestial equator [the projection of the earth’s equator in space] again [e.g. from south to north] after a “year” [crudely 365+ days]). Alternatively, “the period of revolution of the Earth about the Sun with respect to the Vernal Equinox”:

How Many Years Is 1000000 Days

based on the fact that a year is 365.25 days

2737 years 310 and 3/4 days

Answer 6

on an average 1 year=365.25 days

so divide 1,000,000 by 365.25 to get the noof years

=1000000/365.25=2737.85 yrs.approx

Answer 7

1 year = 365.25 days

1million / 365.25 = 2737.8 years

1 year = 365.25 days

1million / 365.25 = 2737.8 years

about 2737 years and 310 or 311 days, depending on what day/year you start at (this is counting leap years)

2739 years and 265 days

1

2740 Years. Anything else?

2

1000000 days = DEEZ NUTZ

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